how to defind dynamic column of this table ( ListView ) ?

I have simple List<string>.
I need to define Table that each column of this table is one of this list elements.
 
So i will use ListView - I need to define a ListView that each column of this ListView is one of my List<string> => that mean that the
 
first column name is List<string>[0]
second column name is List<string>[1]
.
.
.
 
I can't fine any way to do it.
I google it and all the examples are shown how to create dynamic rows
 
Any help please ...